In a first-round encounter at the Mexican Open, world number three Alexander Zverev defeated Jenson Brooksby in three sets, setting a new record for the earliest end to a tennis match.
The ATP event’s first-round tie lasted three hours and 19 minutes, making it the third match on Monday’s schedule to exceed three hours. The match ended at 4:55 a.m. local time in Acapulco, with defending champion Zverev winning 3-6 7-6 (12-10) 6-2. In one hour and 51 minutes, the German won the marathon second set.
At the 2008 Australian Open, Lleyton Hewitt beat Marcos Baghdatis at 4:34 a.m., setting a new record. Because of the heat and humidity, play in Acapulco does not begin until 6 p.m. local time
All three of Monday’s Centre Court matches lasted more than three hours. When the doubles match scheduled for Tuesday had already concluded in Dubai. It is 10 hours ahead of Acapulco, Zverev and Brooksby were still playing.
Brooksby of the United States won the first set. But in the second-set tie-break, she had two match points come and go. On his sixth set point, Zverev forced a deciding, winning a set that went 111 minutes. The German world number three was able to break serve twice in the third set.
The three-hour, 20-minute encounter between Zverev, 24, and Brooksby, 21, of the United States, began at 1:35 a.m., one minute short of the longest match in Mexican Open history.
Stefan Kozlov upset 2014 winner Grigor Dimitrov 7-6 (10-8) 5-7 6-3 earlier on Monday to break the record. After three hours and 14 minutes, John Isner beat Fernando Verdasco. The point table was 7-5 6-7 (4-7) 7-6 (7-3) to come near to matching that mark. On Wednesday, Alexander Zverev will meet compatriot Peter Gojowczyk.